The talk’s demo is telling: a trivial program with a hardcoded out-of-bounds access on a std::span. Of course hardening catches that. But this is the easiest case imaginable. Show me hardening catching a use-after-free through a raw pointer to a pool-allocated object in a real trading system. It can’t, because that’s outside its scope.
Number (5): Everything in this green space must add up to 5. The answer is 3-1, placed horizontally; 4-5, placed horizontally.，推荐阅读立即前往 WhatsApp 網頁版获取更多信息
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